It’s difficult to argue against Boston Red Sox outfielder Mookie Betts winning AL MVP honors this season. And that’s not what we’re here to do. But it’s tough being Los Angeles Angels outfielder Mike Trout these days. After all, he’s been second-place in MVP voting on four separate occasions. And that puts him in exclusive company. Per theScore’s Jason Wilson, Trout now joins Ted Williams, Stan Musial and Albert Pujols with four runner-up finishes.
But when it comes to consistency, there’s nobody better than Trout. Across seven full seasons, he’s been top 5 in MVP voting all seven times. He’s been top 2 on six occasions — with one fourth-place finish in 2017. During that stretch of excellence, he’s slashing .310/.420/.579 with 218 doubles, 244 home runs and 185 stolen bases. His per 162 game averages look like this: 123 runs, 35 doubles, seven triples, 38 home runs and 30 stolen bases.
Yes, Betts did arguably have the best year of any hitter this past season. And yes, it’s hard to argue against his case for MVP. But there is just no denying that Trout is the most excellent, most consistent player in the majors today. Nobody can take that title away from him. Just like nobody can apparently take his second-place finish.
But will he have better fortune next season?